Base | Representation |
---|---|
bin | 1010111100000110010101… |
… | …1100111001010111111101 |
3 | 1120120211100212002222000211 |
4 | 2233001211130321113331 |
5 | 3034030021242041103 |
6 | 41325224042552421 |
7 | 2350652254266544 |
oct | 257014534712775 |
9 | 46524325088024 |
10 | 12027610502653 |
11 | 391797662a139 |
12 | 1423046508711 |
13 | 693277a05615 |
14 | 2d81d493d15b |
15 | 15ccebd9a36d |
hex | af0657395fd |
12027610502653 has 2 divisors, whose sum is σ = 12027610502654. Its totient is φ = 12027610502652.
The previous prime is 12027610502629. The next prime is 12027610502683. The reversal of 12027610502653 is 35620501672021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6529650081124 + 5497960421529 = 2555318^2 + 2344773^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12027610502653 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12027610502683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6013805251326 + 6013805251327.
It is an arithmetic number, because the mean of its divisors is an integer number (6013805251327).
Almost surely, 212027610502653 is an apocalyptic number.
It is an amenable number.
12027610502653 is a deficient number, since it is larger than the sum of its proper divisors (1).
12027610502653 is an equidigital number, since it uses as much as digits as its factorization.
12027610502653 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 151200, while the sum is 40.
The spelling of 12027610502653 in words is "twelve trillion, twenty-seven billion, six hundred ten million, five hundred two thousand, six hundred fifty-three".
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