Base | Representation |
---|---|
bin | 1010111100001111101010… |
… | …0000101110000111011111 |
3 | 1120121001211010211011012101 |
4 | 2233003322200232013133 |
5 | 3034100131443412203 |
6 | 41330320135545531 |
7 | 2351101241641132 |
oct | 257037240560737 |
9 | 46531733734171 |
10 | 12030111310303 |
11 | 3918a3a234a19 |
12 | 1423623b2b2a7 |
13 | 693585b58568 |
14 | 2d8390b20219 |
15 | 15cde66d541d |
hex | af0fa82e1df |
12030111310303 has 2 divisors, whose sum is σ = 12030111310304. Its totient is φ = 12030111310302.
The previous prime is 12030111310213. The next prime is 12030111310309. The reversal of 12030111310303 is 30301311103021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12030111310303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12030111310309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6015055655151 + 6015055655152.
It is an arithmetic number, because the mean of its divisors is an integer number (6015055655152).
Almost surely, 212030111310303 is an apocalyptic number.
12030111310303 is a deficient number, since it is larger than the sum of its proper divisors (1).
12030111310303 is an equidigital number, since it uses as much as digits as its factorization.
12030111310303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 12030111310303 its reverse (30301311103021), we get a palindrome (42331422413324).
The spelling of 12030111310303 in words is "twelve trillion, thirty billion, one hundred eleven million, three hundred ten thousand, three hundred three".
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