Base | Representation |
---|---|
bin | 1010111100010011101101… |
… | …1110110000101001101111 |
3 | 1120121011122002212011010222 |
4 | 2233010323132300221233 |
5 | 3034104400014043224 |
6 | 41331020234321555 |
7 | 2351140245555515 |
oct | 257047336605157 |
9 | 46534562764128 |
10 | 12031201315439 |
11 | 3919449542a09 |
12 | 1423888b892bb |
13 | 6936ca919b07 |
14 | 2d84557ba4b5 |
15 | 15ce5c244b5e |
hex | af13b7b0a6f |
12031201315439 has 2 divisors, whose sum is σ = 12031201315440. Its totient is φ = 12031201315438.
The previous prime is 12031201315421. The next prime is 12031201315451. The reversal of 12031201315439 is 93451310213021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12031201315439 - 28 = 12031201315183 is a prime.
It is a super-2 number, since 2×120312013154392 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12031201315399 and 12031201315408.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12031201315499) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6015600657719 + 6015600657720.
It is an arithmetic number, because the mean of its divisors is an integer number (6015600657720).
Almost surely, 212031201315439 is an apocalyptic number.
12031201315439 is a deficient number, since it is larger than the sum of its proper divisors (1).
12031201315439 is an equidigital number, since it uses as much as digits as its factorization.
12031201315439 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19440, while the sum is 35.
The spelling of 12031201315439 in words is "twelve trillion, thirty-one billion, two hundred one million, three hundred fifteen thousand, four hundred thirty-nine".
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