Base | Representation |
---|---|
bin | 10001100000100000001… |
… | …101010110010111010011 |
3 | 11021000111021122020002012 |
4 | 101200200031112113103 |
5 | 124203003042311032 |
6 | 2320413313213135 |
7 | 152631466401464 |
oct | 21404015262723 |
9 | 4230437566065 |
10 | 1203131213267 |
11 | 424277227a55 |
12 | 1752122611ab |
13 | 895bb221019 |
14 | 42336328d6b |
15 | 21469a4c6b2 |
hex | 118203565d3 |
1203131213267 has 2 divisors, whose sum is σ = 1203131213268. Its totient is φ = 1203131213266.
The previous prime is 1203131213257. The next prime is 1203131213311. The reversal of 1203131213267 is 7623121313021.
It is a weak prime.
It is an emirp because it is prime and its reverse (7623121313021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1203131213267 - 210 = 1203131212243 is a prime.
It is not a weakly prime, because it can be changed into another prime (1203131213257) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601565606633 + 601565606634.
It is an arithmetic number, because the mean of its divisors is an integer number (601565606634).
Almost surely, 21203131213267 is an apocalyptic number.
1203131213267 is a deficient number, since it is larger than the sum of its proper divisors (1).
1203131213267 is an equidigital number, since it uses as much as digits as its factorization.
1203131213267 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9072, while the sum is 32.
Adding to 1203131213267 its reverse (7623121313021), we get a palindrome (8826252526288).
The spelling of 1203131213267 in words is "one trillion, two hundred three billion, one hundred thirty-one million, two hundred thirteen thousand, two hundred sixty-seven".
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