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12031323220031 is a prime number
BaseRepresentation
bin1010111100010100001010…
…1111110010100000111111
31120121011221121020112210212
42233011002233302200333
53034110122221020111
641331040311223035
72351143256001503
oct257050257624077
946534847215725
1012031323220031
113919501335705
121423901977a7b
13693719c5c8cb
142d8467a70303
1515ce67cc498b
hexaf142bf283f

12031323220031 has 2 divisors, whose sum is σ = 12031323220032. Its totient is φ = 12031323220030.

The previous prime is 12031323220027. The next prime is 12031323220051. The reversal of 12031323220031 is 13002232313021.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12031323220031 - 22 = 12031323220027 is a prime.

It is a super-2 number, since 2×120313232200312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12031323219979 and 12031323220006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12031323220051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6015661610015 + 6015661610016.

It is an arithmetic number, because the mean of its divisors is an integer number (6015661610016).

Almost surely, 212031323220031 is an apocalyptic number.

12031323220031 is a deficient number, since it is larger than the sum of its proper divisors (1).

12031323220031 is an equidigital number, since it uses as much as digits as its factorization.

12031323220031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 12031323220031 its reverse (13002232313021), we get a palindrome (25033555533052).

The spelling of 12031323220031 in words is "twelve trillion, thirty-one billion, three hundred twenty-three million, two hundred twenty thousand, thirty-one".