1203136548917 has 2 divisors, whose sum is σ = 1203136548918. Its totient is φ = 1203136548916.

The previous prime is 1203136548871. The next prime is 1203136548931. The reversal of 1203136548917 is 7198456313021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1151316124036 + 51820424881 = 1072994^2 + 227641^2 .

It is a cyclic number.

It is not a de Polignac number, because 1203136548917 - 2¹⁸ = 1203136286773 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1203136548967) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601568274458 + 601568274459.

It is an arithmetic number, because the mean of its divisors is an integer number (601568274459).

It is a 1-persistent number, because it is pandigital, but 2⋅1203136548917 = 2406273097834 is not.

Almost surely, 2^{1203136548917} is an apocalyptic number.

It is an amenable number.

1203136548917 is a deficient number, since it is larger than the sum of its proper divisors (1).

1203136548917 is an equidigital number, since it uses as much as digits as its factorization.

1203136548917 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1088640, while the sum is 50.

The spelling of 1203136548917 in words is "one trillion, two hundred three billion, one hundred thirty-six million, five hundred forty-eight thousand, nine hundred seventeen".