12032002113120 has 576 divisors, whose sum is σ = 45822947788800. Its totient is φ = 2849916825600.

The previous prime is 12032002113007. The next prime is 12032002113127. The reversal of 12032002113120 is 2131120023021.

12032002113120 is a `hidden beast` number, since 1 + 20 + 320 + 0 + 2 + 11 + 312 + 0 = 666.

It is a super-3 number, since 3×12032002113120³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 12032002113093 and 12032002113102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12032002113127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 445930030 + ... + 445957010.

It is an arithmetic number, because the mean of its divisors is an integer number (79553728800).

Almost surely, 2^{12032002113120} is an apocalyptic number.

12032002113120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12032002113120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22911473894400).

12032002113120 is an abundant number, since it is smaller than the sum of its proper divisors (33790945675680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12032002113120 is a wasteful number, since it uses less digits than its factorization.

12032002113120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27659 (or 27648 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 12032002113120 its reverse (2131120023021), we get a palindrome (14163122136141).

The spelling of 12032002113120 in words is "twelve trillion, thirty-two billion, two million, one hundred thirteen thousand, one hundred twenty".