Base | Representation |
---|---|
bin | 111000000001111010… |
… | …0001101000111011011 |
3 | 102111120112010211221121 |
4 | 1300003310031013123 |
5 | 3432410203214042 |
6 | 131135313350111 |
7 | 11456501325154 |
oct | 1600364150733 |
9 | 374515124847 |
10 | 120323101147 |
11 | 47035287867 |
12 | 1b39bb68337 |
13 | b467112c92 |
14 | 5b7621092b |
15 | 31e3529367 |
hex | 1c03d0d1db |
120323101147 has 2 divisors, whose sum is σ = 120323101148. Its totient is φ = 120323101146.
The previous prime is 120323101121. The next prime is 120323101153. The reversal of 120323101147 is 741101323021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120323101147 is a prime.
It is not a weakly prime, because it can be changed into another prime (120623101147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60161550573 + 60161550574.
It is an arithmetic number, because the mean of its divisors is an integer number (60161550574).
Almost surely, 2120323101147 is an apocalyptic number.
120323101147 is a deficient number, since it is larger than the sum of its proper divisors (1).
120323101147 is an equidigital number, since it uses as much as digits as its factorization.
120323101147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 120323101147 its reverse (741101323021), we get a palindrome (861424424168).
The spelling of 120323101147 in words is "one hundred twenty billion, three hundred twenty-three million, one hundred one thousand, one hundred forty-seven".
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