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1203232425943 is a prime number
BaseRepresentation
bin10001100000100110001…
…111011100011111010111
311021000202100002100202211
4101200212033130133113
5124203210000112233
62320431330414251
7152634135604252
oct21404617343727
94230670070684
101203232425943
11424319377599
12175240131387
138960619a792
1442345954099
15214738915cd
hex118263dc7d7

1203232425943 has 2 divisors, whose sum is σ = 1203232425944. Its totient is φ = 1203232425942.

The previous prime is 1203232425917. The next prime is 1203232425947. The reversal of 1203232425943 is 3495242323021.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1203232425943 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1203232425896 and 1203232425905.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1203232425947) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601616212971 + 601616212972.

It is an arithmetic number, because the mean of its divisors is an integer number (601616212972).

Almost surely, 21203232425943 is an apocalyptic number.

1203232425943 is a deficient number, since it is larger than the sum of its proper divisors (1).

1203232425943 is an equidigital number, since it uses as much as digits as its factorization.

1203232425943 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 311040, while the sum is 40.

Adding to 1203232425943 its reverse (3495242323021), we get a palindrome (4698474748964).

The spelling of 1203232425943 in words is "one trillion, two hundred three billion, two hundred thirty-two million, four hundred twenty-five thousand, nine hundred forty-three".