Base | Representation |
---|---|
bin | 11011010111000011111010… |
… | …111001000000100000001111 |
3 | 120210001121221212211121202222 |
4 | 123113003322321000200033 |
5 | 111233004430312404012 |
6 | 1103531432540005555 |
7 | 34226462313216125 |
oct | 3327037271004017 |
9 | 523047855747688 |
10 | 120332013013007 |
11 | 3538357a329a54 |
12 | 115b51978308bb |
13 | 521b34c6a2b13 |
14 | 21a0159b01915 |
15 | dda1a2521972 |
hex | 6d70fae4080f |
120332013013007 has 2 divisors, whose sum is σ = 120332013013008. Its totient is φ = 120332013013006.
The previous prime is 120332013012989. The next prime is 120332013013027. The reversal of 120332013013007 is 700310310233021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120332013013007 - 224 = 120331996235791 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120332013013027) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60166006506503 + 60166006506504.
It is an arithmetic number, because the mean of its divisors is an integer number (60166006506504).
Almost surely, 2120332013013007 is an apocalyptic number.
120332013013007 is a deficient number, since it is larger than the sum of its proper divisors (1).
120332013013007 is an equidigital number, since it uses as much as digits as its factorization.
120332013013007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2268, while the sum is 26.
Adding to 120332013013007 its reverse (700310310233021), we get a palindrome (820642323246028).
The spelling of 120332013013007 in words is "one hundred twenty trillion, three hundred thirty-two billion, thirteen million, thirteen thousand, seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.087 sec. • engine limits •