Base | Representation |
---|---|
bin | 1010111100011011100100… |
… | …1111000111010111111111 |
3 | 1120121101002010212112001011 |
4 | 2233012321033013113333 |
5 | 3034123210123042143 |
6 | 41332005443300051 |
7 | 2351243445034513 |
oct | 257067117072777 |
9 | 46541063775034 |
10 | 12033311143423 |
11 | 391a3314839a9 |
12 | 142417767a627 |
13 | 693975a6913b |
14 | 2d85b5aa4143 |
15 | 15d03259de9d |
hex | af1b93c75ff |
12033311143423 has 2 divisors, whose sum is σ = 12033311143424. Its totient is φ = 12033311143422.
The previous prime is 12033311143361. The next prime is 12033311143429. The reversal of 12033311143423 is 32434111333021.
It is a strong prime.
It is an emirp because it is prime and its reverse (32434111333021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12033311143423 - 229 = 12032774272511 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12033311143429) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6016655571711 + 6016655571712.
It is an arithmetic number, because the mean of its divisors is an integer number (6016655571712).
Almost surely, 212033311143423 is an apocalyptic number.
12033311143423 is a deficient number, since it is larger than the sum of its proper divisors (1).
12033311143423 is an equidigital number, since it uses as much as digits as its factorization.
12033311143423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 12033311143423 its reverse (32434111333021), we get a palindrome (44467422476444).
The spelling of 12033311143423 in words is "twelve trillion, thirty-three billion, three hundred eleven million, one hundred forty-three thousand, four hundred twenty-three".
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