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120340131014203 is a prime number
BaseRepresentation
bin11011010111001011011110…
…110000101110011000111011
3120210002101220122021210212221
4123113023132300232120323
5111233123042014423303
61103535254252544511
734230200426124112
oct3327133660563073
9523071818253787
10120340131014203
1135386a65773451
12115b6882482137
13521c0444c0119
1421a06c9d24c79
15dda4ca07a4bd
hex6d72dec2e63b

120340131014203 has 2 divisors, whose sum is σ = 120340131014204. Its totient is φ = 120340131014202.

The previous prime is 120340131014099. The next prime is 120340131014219. The reversal of 120340131014203 is 302410131043021.

It is a strong prime.

It is an emirp because it is prime and its reverse (302410131043021) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120340131014203 is a prime.

It is a super-2 number, since 2×1203401310142032 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (120340131014503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60170065507101 + 60170065507102.

It is an arithmetic number, because the mean of its divisors is an integer number (60170065507102).

Almost surely, 2120340131014203 is an apocalyptic number.

120340131014203 is a deficient number, since it is larger than the sum of its proper divisors (1).

120340131014203 is an equidigital number, since it uses as much as digits as its factorization.

120340131014203 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 120340131014203 its reverse (302410131043021), we get a palindrome (422750262057224).

The spelling of 120340131014203 in words is "one hundred twenty trillion, three hundred forty billion, one hundred thirty-one million, fourteen thousand, two hundred three".