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12034547531213 is a prime number
BaseRepresentation
bin1010111100100000001011…
…1011100011110111001101
31120121111021022100112020112
42233020002323203313031
53034133223131444323
641332332251325405
72351316210124604
oct257100273436715
946544238315215
1012034547531213
11391a906383399
121424461750865
13693b11c60c4c
142d8691d86a3b
1515d0a5dc6178
hexaf202ee3dcd

12034547531213 has 2 divisors, whose sum is σ = 12034547531214. Its totient is φ = 12034547531212.

The previous prime is 12034547531119. The next prime is 12034547531233. The reversal of 12034547531213 is 31213574543021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11463248890564 + 571298640649 = 3385742^2 + 755843^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12034547531213 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12034547531233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6017273765606 + 6017273765607.

It is an arithmetic number, because the mean of its divisors is an integer number (6017273765607).

Almost surely, 212034547531213 is an apocalyptic number.

It is an amenable number.

12034547531213 is a deficient number, since it is larger than the sum of its proper divisors (1).

12034547531213 is an equidigital number, since it uses as much as digits as its factorization.

12034547531213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 302400, while the sum is 41.

The spelling of 12034547531213 in words is "twelve trillion, thirty-four billion, five hundred forty-seven million, five hundred thirty-one thousand, two hundred thirteen".