120351404933 has 2 divisors, whose sum is σ = 120351404934. Its totient is φ = 120351404932.

The previous prime is 120351404867. The next prime is 120351404947. The reversal of 120351404933 is 339404153021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 118512882049 + 1838522884 = 344257^2 + 42878^2 .

It is a cyclic number.

It is not a de Polignac number, because 120351404933 - 2¹² = 120351400837 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 120351404893 and 120351404902.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120351407933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60175702466 + 60175702467.

It is an arithmetic number, because the mean of its divisors is an integer number (60175702467).

Almost surely, 2^120351404933 is an apocalyptic number.

It is an amenable number.

120351404933 is a deficient number, since it is larger than the sum of its proper divisors (1).

120351404933 is an equidigital number, since it uses as much as digits as its factorization.

120351404933 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38880, while the sum is 35.

Adding to 120351404933 its reverse (339404153021), we get a palindrome (459755557954).

The spelling of 120351404933 in words is "one hundred twenty billion, three hundred fifty-one million, four hundred four thousand, nine hundred thirty-three".