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120373035215453 is a prime number
BaseRepresentation
bin11011010111101010001000…
…000000010010101001011101
3120210012112211210100102102022
4123113222020000102221131
5111234142434003343303
61104002335312105525
734232444012202026
oct3327521000225135
9523175753312368
10120373035215453
1135399a102958a9
1211601125b352a5
1352221894672a7
1421a212bd59c4d
15ddb2a3b23438
hex6d7a88012a5d

120373035215453 has 2 divisors, whose sum is σ = 120373035215454. Its totient is φ = 120373035215452.

The previous prime is 120373035215431. The next prime is 120373035215551. The reversal of 120373035215453 is 354512530373021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 116418338211289 + 3954697004164 = 10789733^2 + 1988642^2 .

It is a cyclic number.

It is not a de Polignac number, because 120373035215453 - 224 = 120373018438237 is a prime.

It is a super-2 number, since 2×1203730352154532 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120373035215413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60186517607726 + 60186517607727.

It is an arithmetic number, because the mean of its divisors is an integer number (60186517607727).

Almost surely, 2120373035215453 is an apocalyptic number.

It is an amenable number.

120373035215453 is a deficient number, since it is larger than the sum of its proper divisors (1).

120373035215453 is an equidigital number, since it uses as much as digits as its factorization.

120373035215453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1134000, while the sum is 44.

Adding to 120373035215453 its reverse (354512530373021), we get a palindrome (474885565588474).

The spelling of 120373035215453 in words is "one hundred twenty trillion, three hundred seventy-three billion, thirty-five million, two hundred fifteen thousand, four hundred fifty-three".