Base | Representation |
---|---|
bin | 10001100001000111110… |
… | …110001110111001011101 |
3 | 11021002012122000012000111 |
4 | 101201013312032321131 |
5 | 124210333314221023 |
6 | 2321003311130021 |
7 | 152654123141011 |
oct | 21410766167135 |
9 | 4232178005014 |
10 | 1203796242013 |
11 | 424588660992 |
12 | 175378b13911 |
13 | 89695c37761 |
14 | 4239a79c541 |
15 | 214a811300d |
hex | 11847d8ee5d |
1203796242013 has 2 divisors, whose sum is σ = 1203796242014. Its totient is φ = 1203796242012.
The previous prime is 1203796241987. The next prime is 1203796242037. The reversal of 1203796242013 is 3102426973021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 721789574724 + 482006667289 = 849582^2 + 694267^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1203796242013 is a prime.
It is a super-3 number, since 3×12037962420133 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1203796240013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601898121006 + 601898121007.
It is an arithmetic number, because the mean of its divisors is an integer number (601898121007).
Almost surely, 21203796242013 is an apocalyptic number.
It is an amenable number.
1203796242013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1203796242013 is an equidigital number, since it uses as much as digits as its factorization.
1203796242013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108864, while the sum is 40.
The spelling of 1203796242013 in words is "one trillion, two hundred three billion, seven hundred ninety-six million, two hundred forty-two thousand, thirteen".
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