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1203796242013 is a prime number
BaseRepresentation
bin10001100001000111110…
…110001110111001011101
311021002012122000012000111
4101201013312032321131
5124210333314221023
62321003311130021
7152654123141011
oct21410766167135
94232178005014
101203796242013
11424588660992
12175378b13911
1389695c37761
144239a79c541
15214a811300d
hex11847d8ee5d

1203796242013 has 2 divisors, whose sum is σ = 1203796242014. Its totient is φ = 1203796242012.

The previous prime is 1203796241987. The next prime is 1203796242037. The reversal of 1203796242013 is 3102426973021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 721789574724 + 482006667289 = 849582^2 + 694267^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1203796242013 is a prime.

It is a super-3 number, since 3×12037962420133 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1203796240013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601898121006 + 601898121007.

It is an arithmetic number, because the mean of its divisors is an integer number (601898121007).

Almost surely, 21203796242013 is an apocalyptic number.

It is an amenable number.

1203796242013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1203796242013 is an equidigital number, since it uses as much as digits as its factorization.

1203796242013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108864, while the sum is 40.

The spelling of 1203796242013 in words is "one trillion, two hundred three billion, seven hundred ninety-six million, two hundred forty-two thousand, thirteen".