Base | Representation |
---|---|
bin | 10001100001010100110… |
… | …001111010100101011011 |
3 | 11021002202202021111200121 |
4 | 101201110301322211123 |
5 | 124211304340322133 |
6 | 2321041021414111 |
7 | 152662366313353 |
oct | 21412461724533 |
9 | 4232682244617 |
10 | 1204013214043 |
11 | 42468a086212 |
12 | 17541970a337 |
13 | 896cbb84b83 |
14 | 423bb51bb63 |
15 | 214bc1c102d |
hex | 11854c7a95b |
1204013214043 has 2 divisors, whose sum is σ = 1204013214044. Its totient is φ = 1204013214042.
The previous prime is 1204013213987. The next prime is 1204013214059. The reversal of 1204013214043 is 3404123104021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1204013214043 - 217 = 1204013082971 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1204013213999 and 1204013214017.
It is not a weakly prime, because it can be changed into another prime (1204013214343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 602006607021 + 602006607022.
It is an arithmetic number, because the mean of its divisors is an integer number (602006607022).
Almost surely, 21204013214043 is an apocalyptic number.
1204013214043 is a deficient number, since it is larger than the sum of its proper divisors (1).
1204013214043 is an equidigital number, since it uses as much as digits as its factorization.
1204013214043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 1204013214043 its reverse (3404123104021), we get a palindrome (4608136318064).
The spelling of 1204013214043 in words is "one trillion, two hundred four billion, thirteen million, two hundred fourteen thousand, forty-three".
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