Base | Representation |
---|---|
bin | 11011011000000110111101… |
… | …101001101001011010100101 |
3 | 120210022111202210002111000002 |
4 | 123120012331221221122211 |
5 | 111240144343001121013 |
6 | 1104024500051231045 |
7 | 34234621235534354 |
oct | 3330067551513245 |
9 | 523274683074002 |
10 | 120404000020133 |
11 | 354010600a3975 |
12 | 11607127ba8485 |
13 | 522508269591b |
14 | 21a382858d99b |
15 | ddbeb72ca358 |
hex | 6d81bda696a5 |
120404000020133 has 2 divisors, whose sum is σ = 120404000020134. Its totient is φ = 120404000020132.
The previous prime is 120404000020081. The next prime is 120404000020147. The reversal of 120404000020133 is 331020000404021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 106181009709889 + 14222990310244 = 10304417^2 + 3771338^2 .
It is a cyclic number.
It is not a de Polignac number, because 120404000020133 - 236 = 120335280543397 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120404000020153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60202000010066 + 60202000010067.
It is an arithmetic number, because the mean of its divisors is an integer number (60202000010067).
Almost surely, 2120404000020133 is an apocalyptic number.
It is an amenable number.
120404000020133 is a deficient number, since it is larger than the sum of its proper divisors (1).
120404000020133 is an equidigital number, since it uses as much as digits as its factorization.
120404000020133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 20.
Adding to 120404000020133 its reverse (331020000404021), we get a palindrome (451424000424154).
The spelling of 120404000020133 in words is "one hundred twenty trillion, four hundred four billion, twenty thousand, one hundred thirty-three".
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