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120404000020133 is a prime number
BaseRepresentation
bin11011011000000110111101…
…101001101001011010100101
3120210022111202210002111000002
4123120012331221221122211
5111240144343001121013
61104024500051231045
734234621235534354
oct3330067551513245
9523274683074002
10120404000020133
11354010600a3975
1211607127ba8485
13522508269591b
1421a382858d99b
15ddbeb72ca358
hex6d81bda696a5

120404000020133 has 2 divisors, whose sum is σ = 120404000020134. Its totient is φ = 120404000020132.

The previous prime is 120404000020081. The next prime is 120404000020147. The reversal of 120404000020133 is 331020000404021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 106181009709889 + 14222990310244 = 10304417^2 + 3771338^2 .

It is a cyclic number.

It is not a de Polignac number, because 120404000020133 - 236 = 120335280543397 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120404000020153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60202000010066 + 60202000010067.

It is an arithmetic number, because the mean of its divisors is an integer number (60202000010067).

Almost surely, 2120404000020133 is an apocalyptic number.

It is an amenable number.

120404000020133 is a deficient number, since it is larger than the sum of its proper divisors (1).

120404000020133 is an equidigital number, since it uses as much as digits as its factorization.

120404000020133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 120404000020133 its reverse (331020000404021), we get a palindrome (451424000424154).

The spelling of 120404000020133 in words is "one hundred twenty trillion, four hundred four billion, twenty thousand, one hundred thirty-three".