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120410142451 is a prime number
BaseRepresentation
bin111000000100100000…
…0001111011011110011
3102111210120221000011121
41300021000033123303
53433044444024301
6131152103123111
711461606215664
oct1601100173363
9374716830147
10120410142451
114707a428225
121b405143497
13b47c16a301
145b839cb36b
1531eaebe3a1
hex1c0900f6f3

120410142451 has 2 divisors, whose sum is σ = 120410142452. Its totient is φ = 120410142450.

The previous prime is 120410142407. The next prime is 120410142487. The reversal of 120410142451 is 154241014021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 120410142451 - 29 = 120410141939 is a prime.

It is a super-2 number, since 2×1204101424512 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (120410142551) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60205071225 + 60205071226.

It is an arithmetic number, because the mean of its divisors is an integer number (60205071226).

Almost surely, 2120410142451 is an apocalyptic number.

120410142451 is a deficient number, since it is larger than the sum of its proper divisors (1).

120410142451 is an equidigital number, since it uses as much as digits as its factorization.

120410142451 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1280, while the sum is 25.

Adding to 120410142451 its reverse (154241014021), we get a palindrome (274651156472).

The spelling of 120410142451 in words is "one hundred twenty billion, four hundred ten million, one hundred forty-two thousand, four hundred fifty-one".