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12041102433223 is a prime number
BaseRepresentation
bin1010111100111000100110…
…1000100001101111000111
31120122010012010120001101001
42233032021220201233013
53034240134210330343
641335334525514131
72351640512642233
oct257161150415707
946563163501331
1012041102433223
11392266a45a286
121425790a12947
13694617c954a6
142d8b1475d5c3
1515d33b5be44d
hexaf389a21bc7

12041102433223 has 2 divisors, whose sum is σ = 12041102433224. Its totient is φ = 12041102433222.

The previous prime is 12041102433209. The next prime is 12041102433293. The reversal of 12041102433223 is 32233420114021.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12041102433223 - 237 = 11903663479751 is a prime.

It is a super-4 number, since 4×120411024332234 (a number of 53 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12041102433191 and 12041102433200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12041102433293) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6020551216611 + 6020551216612.

It is an arithmetic number, because the mean of its divisors is an integer number (6020551216612).

Almost surely, 212041102433223 is an apocalyptic number.

12041102433223 is a deficient number, since it is larger than the sum of its proper divisors (1).

12041102433223 is an equidigital number, since it uses as much as digits as its factorization.

12041102433223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 12041102433223 its reverse (32233420114021), we get a palindrome (44274522547244).

The spelling of 12041102433223 in words is "twelve trillion, forty-one billion, one hundred two million, four hundred thirty-three thousand, two hundred twenty-three".