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12042221353 is a prime number
BaseRepresentation
bin10110011011100010…
…11011011100101001
31011002020120020011021
423031301123130221
5144130302040403
65310534332441
7604263123031
oct131561333451
934066506137
1012042221353
11511a57a158
122400aba121
13119bb28486
1482348c8c1
154a73108bd
hex2cdc5b729

12042221353 has 2 divisors, whose sum is σ = 12042221354. Its totient is φ = 12042221352.

The previous prime is 12042221327. The next prime is 12042221357. The reversal of 12042221353 is 35312224021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11034031849 + 1008189504 = 105043^2 + 31752^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12042221353 is a prime.

It is a super-4 number, since 4×120422213534 (a number of 41 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (12042221357) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6021110676 + 6021110677.

It is an arithmetic number, because the mean of its divisors is an integer number (6021110677).

Almost surely, 212042221353 is an apocalyptic number.

It is an amenable number.

12042221353 is a deficient number, since it is larger than the sum of its proper divisors (1).

12042221353 is an equidigital number, since it uses as much as digits as its factorization.

12042221353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 12042221353 its reverse (35312224021), we get a palindrome (47354445374).

The spelling of 12042221353 in words is "twelve billion, forty-two million, two hundred twenty-one thousand, three hundred fifty-three".