Base | Representation |
---|---|
bin | 1010111100111101010000… |
… | …0001001111000001000011 |
3 | 1120122020102002212120001112 |
4 | 2233033110001033001003 |
5 | 3034300213202033011 |
6 | 41340102430353535 |
7 | 2352013445456546 |
oct | 257172401170103 |
9 | 46566362776045 |
10 | 12042350424131 |
11 | 392314a964325 |
12 | 1425a7a95b8ab |
13 | 6947866c0751 |
14 | 2d8bd23c285d |
15 | 15d3b0e3958b |
hex | af3d404f043 |
12042350424131 has 2 divisors, whose sum is σ = 12042350424132. Its totient is φ = 12042350424130.
The previous prime is 12042350424107. The next prime is 12042350424227. The reversal of 12042350424131 is 13142405324021.
It is a weak prime.
It is an emirp because it is prime and its reverse (13142405324021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12042350424131 - 218 = 12042350161987 is a prime.
It is a super-2 number, since 2×120423504241312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12042350424101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6021175212065 + 6021175212066.
It is an arithmetic number, because the mean of its divisors is an integer number (6021175212066).
Almost surely, 212042350424131 is an apocalyptic number.
12042350424131 is a deficient number, since it is larger than the sum of its proper divisors (1).
12042350424131 is an equidigital number, since it uses as much as digits as its factorization.
12042350424131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23040, while the sum is 32.
Adding to 12042350424131 its reverse (13142405324021), we get a palindrome (25184755748152).
The spelling of 12042350424131 in words is "twelve trillion, forty-two billion, three hundred fifty million, four hundred twenty-four thousand, one hundred thirty-one".
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