Base | Representation |
---|---|
bin | 10110011011100100… |
… | …10001101001001101 |
3 | 1011002020222111200001 |
4 | 23031302101221031 |
5 | 144130331141331 |
6 | 5310543204301 |
7 | 604265036155 |
oct | 131562215115 |
9 | 34066874601 |
10 | 12042443341 |
11 | 511a710a15 |
12 | 2400ba6691 |
13 | 119bba5526 |
14 | 823509765 |
15 | 4a7356561 |
hex | 2cdc91a4d |
12042443341 has 2 divisors, whose sum is σ = 12042443342. Its totient is φ = 12042443340.
The previous prime is 12042443291. The next prime is 12042443351. The reversal of 12042443341 is 14334424021.
12042443341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11314576900 + 727866441 = 106370^2 + 26979^2 .
It is a cyclic number.
It is not a de Polignac number, because 12042443341 - 211 = 12042441293 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12042443351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6021221670 + 6021221671.
It is an arithmetic number, because the mean of its divisors is an integer number (6021221671).
Almost surely, 212042443341 is an apocalyptic number.
It is an amenable number.
12042443341 is a deficient number, since it is larger than the sum of its proper divisors (1).
12042443341 is an equidigital number, since it uses as much as digits as its factorization.
12042443341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 28.
Adding to 12042443341 its reverse (14334424021), we get a palindrome (26376867362).
The spelling of 12042443341 in words is "twelve billion, forty-two million, four hundred forty-three thousand, three hundred forty-one".
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