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12042648113 is a prime number
BaseRepresentation
bin10110011011100110…
…00011101000110001
31011002021100220120012
423031303003220301
5144130404214423
65310551424305
7604266551156
oct131563035061
934067326505
1012042648113
11511a840851
122401085095
13119bc477b2
1482356022d
154a7397078
hex2cdcc3a31

12042648113 has 2 divisors, whose sum is σ = 12042648114. Its totient is φ = 12042648112.

The previous prime is 12042648109. The next prime is 12042648143. The reversal of 12042648113 is 31184624021.

12042648113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6624657664 + 5417990449 = 81392^2 + 73607^2 .

It is an emirp because it is prime and its reverse (31184624021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12042648113 - 22 = 12042648109 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12042648113.

It is not a weakly prime, because it can be changed into another prime (12042648103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6021324056 + 6021324057.

It is an arithmetic number, because the mean of its divisors is an integer number (6021324057).

Almost surely, 212042648113 is an apocalyptic number.

It is an amenable number.

12042648113 is a deficient number, since it is larger than the sum of its proper divisors (1).

12042648113 is an equidigital number, since it uses as much as digits as its factorization.

12042648113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9216, while the sum is 32.

The spelling of 12042648113 in words is "twelve billion, forty-two million, six hundred forty-eight thousand, one hundred thirteen".