Base | Representation |
---|---|
bin | 10110011011100110… |
… | …00111100100010101 |
3 | 1011002021101201122111 |
4 | 23031303013210111 |
5 | 144130410223323 |
6 | 5310552031021 |
7 | 604266646126 |
oct | 131563074425 |
9 | 34067351574 |
10 | 12042664213 |
11 | 511a851958 |
12 | 2401092471 |
13 | 119bc51c18 |
14 | 82356604d |
15 | 4a739bc0d |
hex | 2cdcc7915 |
12042664213 has 2 divisors, whose sum is σ = 12042664214. Its totient is φ = 12042664212.
The previous prime is 12042664181. The next prime is 12042664229. The reversal of 12042664213 is 31246624021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11087668804 + 954995409 = 105298^2 + 30903^2 .
It is a cyclic number.
It is not a de Polignac number, because 12042664213 - 25 = 12042664181 is a prime.
It is a super-2 number, since 2×120426642132 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12042664273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6021332106 + 6021332107.
It is an arithmetic number, because the mean of its divisors is an integer number (6021332107).
Almost surely, 212042664213 is an apocalyptic number.
It is an amenable number.
12042664213 is a deficient number, since it is larger than the sum of its proper divisors (1).
12042664213 is an equidigital number, since it uses as much as digits as its factorization.
12042664213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 31.
The spelling of 12042664213 in words is "twelve billion, forty-two million, six hundred sixty-four thousand, two hundred thirteen".
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