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120433263133 is a prime number
BaseRepresentation
bin111000000101001100…
…0011100001000011101
3102111212012102122210011
41300022120130020131
53433121403410013
6131154250443221
711462306563141
oct1601230341035
9374765378704
10120433263133
114709148a127
121b410a33511
13b483ba3ca1
145b86ac9221
1531ed039c3d
hex1c0a61c21d

120433263133 has 2 divisors, whose sum is σ = 120433263134. Its totient is φ = 120433263132.

The previous prime is 120433263121. The next prime is 120433263151. The reversal of 120433263133 is 331362334021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 114746142564 + 5687120569 = 338742^2 + 75413^2 .

It is a cyclic number.

It is not a de Polignac number, because 120433263133 - 213 = 120433254941 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 120433263095 and 120433263104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120433263103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60216631566 + 60216631567.

It is an arithmetic number, because the mean of its divisors is an integer number (60216631567).

Almost surely, 2120433263133 is an apocalyptic number.

It is an amenable number.

120433263133 is a deficient number, since it is larger than the sum of its proper divisors (1).

120433263133 is an equidigital number, since it uses as much as digits as its factorization.

120433263133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23328, while the sum is 31.

Adding to 120433263133 its reverse (331362334021), we get a palindrome (451795597154).

The spelling of 120433263133 in words is "one hundred twenty billion, four hundred thirty-three million, two hundred sixty-three thousand, one hundred thirty-three".