Base | Representation |
---|---|
bin | 1010111101000001010011… |
… | …1110111000001101000111 |
3 | 1120122100020001201021120221 |
4 | 2233100110332320031013 |
5 | 3034304431210403242 |
6 | 41340402523005211 |
7 | 2352052451462446 |
oct | 257202476701507 |
9 | 46570201637527 |
10 | 12043440325447 |
11 | 392365a101313 |
12 | 1426123969807 |
13 | 6948cb44697b |
14 | 2d8c97052d5d |
15 | 15d426978167 |
hex | af414fb8347 |
12043440325447 has 2 divisors, whose sum is σ = 12043440325448. Its totient is φ = 12043440325446.
The previous prime is 12043440325409. The next prime is 12043440325487. The reversal of 12043440325447 is 74452304434021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12043440325447 - 215 = 12043440292679 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12043440325487) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6021720162723 + 6021720162724.
It is an arithmetic number, because the mean of its divisors is an integer number (6021720162724).
Almost surely, 212043440325447 is an apocalyptic number.
12043440325447 is a deficient number, since it is larger than the sum of its proper divisors (1).
12043440325447 is an equidigital number, since it uses as much as digits as its factorization.
12043440325447 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1290240, while the sum is 43.
Adding to 12043440325447 its reverse (74452304434021), we get a palindrome (86495744759468).
The spelling of 12043440325447 in words is "twelve trillion, forty-three billion, four hundred forty million, three hundred twenty-five thousand, four hundred forty-seven".
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