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12043455133 is a prime number
BaseRepresentation
bin10110011011101100…
…01000101010011101
31011002022212220120211
423031312020222131
5144131111031013
65311021012421
7604306452043
oct131566105235
934068786524
1012043455133
115120242106
1224013b4111
13119c16ac18
148236d0393
154a74a623d
hex2cdd88a9d

12043455133 has 2 divisors, whose sum is σ = 12043455134. Its totient is φ = 12043455132.

The previous prime is 12043455091. The next prime is 12043455209. The reversal of 12043455133 is 33155434021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8786812644 + 3256642489 = 93738^2 + 57067^2 .

It is an emirp because it is prime and its reverse (33155434021) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12043455133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12043455095 and 12043455104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12043453133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6021727566 + 6021727567.

It is an arithmetic number, because the mean of its divisors is an integer number (6021727567).

Almost surely, 212043455133 is an apocalyptic number.

It is an amenable number.

12043455133 is a deficient number, since it is larger than the sum of its proper divisors (1).

12043455133 is an equidigital number, since it uses as much as digits as its factorization.

12043455133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 12043455133 its reverse (33155434021), we get a palindrome (45198889154).

The spelling of 12043455133 in words is "twelve billion, forty-three million, four hundred fifty-five thousand, one hundred thirty-three".