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120435554093 is a prime number
BaseRepresentation
bin111000000101010000…
…1001011011100101101
3102111212100202001101112
41300022201023130231
53433123000212333
6131154411521405
711462335214261
oct1601241133455
9374770661345
10120435554093
1147092804388
121b411759265
13b4844c699a
145b871240a1
1531ed33d948
hex1c0a84b72d

120435554093 has 2 divisors, whose sum is σ = 120435554094. Its totient is φ = 120435554092.

The previous prime is 120435553963. The next prime is 120435554117. The reversal of 120435554093 is 390455534021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 71911394569 + 48524159524 = 268163^2 + 220282^2 .

It is a cyclic number.

It is not a de Polignac number, because 120435554093 - 226 = 120368445229 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 120435554093.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120435554293) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60217777046 + 60217777047.

It is an arithmetic number, because the mean of its divisors is an integer number (60217777047).

Almost surely, 2120435554093 is an apocalyptic number.

It is an amenable number.

120435554093 is a deficient number, since it is larger than the sum of its proper divisors (1).

120435554093 is an equidigital number, since it uses as much as digits as its factorization.

120435554093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324000, while the sum is 41.

The spelling of 120435554093 in words is "one hundred twenty billion, four hundred thirty-five million, five hundred fifty-four thousand, ninety-three".