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12048204953 is a prime number
BaseRepresentation
bin10110011100010000…
…10000010010011001
31011002122211020010002
423032020100102121
5144133320024303
65311310502345
7604365023651
oct131610202231
934078736102
1012048204953
115122996784
122402b049b5
1311a0141b75
148241a9361
154a7ae3788
hex2ce210499

12048204953 has 2 divisors, whose sum is σ = 12048204954. Its totient is φ = 12048204952.

The previous prime is 12048204943. The next prime is 12048205027. The reversal of 12048204953 is 35940284021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11600797849 + 447407104 = 107707^2 + 21152^2 .

It is a cyclic number.

It is not a de Polignac number, because 12048204953 - 214 = 12048188569 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (12048204943) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6024102476 + 6024102477.

It is an arithmetic number, because the mean of its divisors is an integer number (6024102477).

Almost surely, 212048204953 is an apocalyptic number.

It is an amenable number.

12048204953 is a deficient number, since it is larger than the sum of its proper divisors (1).

12048204953 is an equidigital number, since it uses as much as digits as its factorization.

12048204953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69120, while the sum is 38.

Adding to 12048204953 its reverse (35940284021), we get a palindrome (47988488974).

The spelling of 12048204953 in words is "twelve billion, forty-eight million, two hundred four thousand, nine hundred fifty-three".