Base | Representation |
---|---|
bin | 1010111101011011000011… |
… | …1101101011111001111001 |
3 | 1120200000001202200012112111 |
4 | 2233112300331223321321 |
5 | 3034413110132212123 |
6 | 41343504433012321 |
7 | 2352415650612661 |
oct | 257266075537171 |
9 | 46600052605474 |
10 | 12050352225913 |
11 | 3926586752451 |
12 | 14275326b40a1 |
13 | 6954604149c1 |
14 | 2d9350dd91a1 |
15 | 15d6cd68d90d |
hex | af5b0f6be79 |
12050352225913 has 2 divisors, whose sum is σ = 12050352225914. Its totient is φ = 12050352225912.
The previous prime is 12050352225887. The next prime is 12050352225917. The reversal of 12050352225913 is 31952225305021.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9814705262649 + 2235646963264 = 3132843^2 + 1495208^2 .
It is a cyclic number.
It is not a de Polignac number, because 12050352225913 - 229 = 12049815355001 is a prime.
It is not a weakly prime, because it can be changed into another prime (12050352225917) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6025176112956 + 6025176112957.
It is an arithmetic number, because the mean of its divisors is an integer number (6025176112957).
Almost surely, 212050352225913 is an apocalyptic number.
It is an amenable number.
12050352225913 is a deficient number, since it is larger than the sum of its proper divisors (1).
12050352225913 is an equidigital number, since it uses as much as digits as its factorization.
12050352225913 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162000, while the sum is 40.
The spelling of 12050352225913 in words is "twelve trillion, fifty billion, three hundred fifty-two million, two hundred twenty-five thousand, nine hundred thirteen".
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