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120505706051173 is a prime number
BaseRepresentation
bin11011011001100101101011…
…110011010111011001100101
3120210200020021211221011212121
4123121211223303113121211
5111243331141222114143
61104143320200345541
734245151506534322
oct3331455363273145
9523606254834777
10120505706051173
1135440201541383
12116229911752b1
135231840783a91
1421a8716025b49
15dde96b1aa7ed
hex6d996bcd7665

120505706051173 has 2 divisors, whose sum is σ = 120505706051174. Its totient is φ = 120505706051172.

The previous prime is 120505706051131. The next prime is 120505706051219. The reversal of 120505706051173 is 371150607505021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 71187980666209 + 49317725384964 = 8437297^2 + 7022658^2 .

It is a cyclic number.

It is not a de Polignac number, because 120505706051173 - 217 = 120505705920101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120505706051123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60252853025586 + 60252853025587.

It is an arithmetic number, because the mean of its divisors is an integer number (60252853025587).

Almost surely, 2120505706051173 is an apocalyptic number.

It is an amenable number.

120505706051173 is a deficient number, since it is larger than the sum of its proper divisors (1).

120505706051173 is an equidigital number, since it uses as much as digits as its factorization.

120505706051173 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 220500, while the sum is 43.

The spelling of 120505706051173 in words is "one hundred twenty trillion, five hundred five billion, seven hundred six million, fifty-one thousand, one hundred seventy-three".