1205313433 has 2 divisors, whose sum is σ = 1205313434. Its totient is φ = 1205313432.

The previous prime is 1205313397. The next prime is 1205313437. The reversal of 1205313433 is 3343135021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1199098384 + 6215049 = 34628^2 + 2493^2 .

It is an emirp because it is prime and its reverse (3343135021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1205313433 - 2⁹ = 1205312921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1205313398 and 1205313407.

It is not a weakly prime, because it can be changed into another prime (1205313437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 602656716 + 602656717.

It is an arithmetic number, because the mean of its divisors is an integer number (602656717).

Almost surely, 2^1205313433 is an apocalyptic number.

It is an amenable number.

1205313433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1205313433 is an equidigital number, since it uses as much as digits as its factorization.

1205313433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3240, while the sum is 25.

The square root of 1205313433 is about 34717.6242418746. The cubic root of 1205313433 is about 1064.2246946760.

Adding to 1205313433 its reverse (3343135021), we get a palindrome (4548448454).

The spelling of 1205313433 in words is "one billion, two hundred five million, three hundred thirteen thousand, four hundred thirty-three".