Base | Representation |
---|---|
bin | 10110011100110111… |
… | …01111011110101001 |
3 | 1011010000102202122122 |
4 | 23032123233132221 |
5 | 144141122012244 |
6 | 5312012201025 |
7 | 604456321352 |
oct | 131633573651 |
9 | 34100382578 |
10 | 12053313449 |
11 | 5125865881 |
12 | 2404769175 |
13 | 11a1210148 |
14 | 824b38d29 |
15 | 4a82a21ee |
hex | 2ce6ef7a9 |
12053313449 has 2 divisors, whose sum is σ = 12053313450. Its totient is φ = 12053313448.
The previous prime is 12053313443. The next prime is 12053313451. The reversal of 12053313449 is 94431335021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9676263424 + 2377050025 = 98368^2 + 48755^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12053313449 is a prime.
Together with 12053313451, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (12053313443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6026656724 + 6026656725.
It is an arithmetic number, because the mean of its divisors is an integer number (6026656725).
Almost surely, 212053313449 is an apocalyptic number.
It is an amenable number.
12053313449 is a deficient number, since it is larger than the sum of its proper divisors (1).
12053313449 is an equidigital number, since it uses as much as digits as its factorization.
12053313449 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38880, while the sum is 35.
The spelling of 12053313449 in words is "twelve billion, fifty-three million, three hundred thirteen thousand, four hundred forty-nine".
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