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12065459993 is a prime number
BaseRepresentation
bin10110011110010100…
…00100111100011001
31011010212021212120122
423033022010330121
5144202224204433
65313124403025
7604664501126
oct131712047431
934125255518
1012065459993
115131701744
122408846475
1311a38a3a52
148265bb74d
154a93a1198
hex2cf284f19

12065459993 has 2 divisors, whose sum is σ = 12065459994. Its totient is φ = 12065459992.

The previous prime is 12065459983. The next prime is 12065460013. The reversal of 12065459993 is 39995456021.

12065459993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6457247449 + 5608212544 = 80357^2 + 74888^2 .

It is an emirp because it is prime and its reverse (39995456021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12065459993 - 210 = 12065458969 is a prime.

It is not a weakly prime, because it can be changed into another prime (12065459983) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6032729996 + 6032729997.

It is an arithmetic number, because the mean of its divisors is an integer number (6032729997).

Almost surely, 212065459993 is an apocalyptic number.

It is an amenable number.

12065459993 is a deficient number, since it is larger than the sum of its proper divisors (1).

12065459993 is an equidigital number, since it uses as much as digits as its factorization.

12065459993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2624400, while the sum is 53.

The spelling of 12065459993 in words is "twelve billion, sixty-five million, four hundred fifty-nine thousand, nine hundred ninety-three".