Base | Representation |
---|---|
bin | 11011011011111111101110… |
… | …101101101000101001010101 |
3 | 120211021001020012202100110011 |
4 | 123123333232231220221111 |
5 | 111304033413421341433 |
6 | 1104351313153200221 |
7 | 34263125424455122 |
oct | 3333775655505125 |
9 | 524231205670404 |
10 | 120671111121493 |
11 | 354a437037a8a9 |
12 | 1164aa52b60071 |
13 | 524431077765a |
14 | 21b2727721749 |
15 | de3dec4153cd |
hex | 6dbfeeb68a55 |
120671111121493 has 2 divisors, whose sum is σ = 120671111121494. Its totient is φ = 120671111121492.
The previous prime is 120671111121479. The next prime is 120671111121523. The reversal of 120671111121493 is 394121111176021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 63449859353764 + 57221251767729 = 7965542^2 + 7564473^2 .
It is a cyclic number.
It is not a de Polignac number, because 120671111121493 - 233 = 120662521186901 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120671111121403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60335555560746 + 60335555560747.
It is an arithmetic number, because the mean of its divisors is an integer number (60335555560747).
Almost surely, 2120671111121493 is an apocalyptic number.
It is an amenable number.
120671111121493 is a deficient number, since it is larger than the sum of its proper divisors (1).
120671111121493 is an equidigital number, since it uses as much as digits as its factorization.
120671111121493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 40.
The spelling of 120671111121493 in words is "one hundred twenty trillion, six hundred seventy-one billion, one hundred eleven million, one hundred twenty-one thousand, four hundred ninety-three".
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