Base | Representation |
---|---|
bin | 1010111110111001000000… |
… | …1011111111001010111101 |
3 | 1120202102011101101002201111 |
4 | 2233232100023333022331 |
5 | 3040321232431133433 |
6 | 41403235151042021 |
7 | 2354300635352404 |
oct | 257562013771275 |
9 | 46672141332644 |
10 | 12075572130493 |
11 | 3936248726aa3 |
12 | 14303b0810311 |
13 | 69794c384371 |
14 | 2da66466663b |
15 | 15e1a77ecdcd |
hex | afb902ff2bd |
12075572130493 has 2 divisors, whose sum is σ = 12075572130494. Its totient is φ = 12075572130492.
The previous prime is 12075572130473. The next prime is 12075572130541. The reversal of 12075572130493 is 39403127557021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9988362030969 + 2087210099524 = 3160437^2 + 1444718^2 .
It is a cyclic number.
It is not a de Polignac number, because 12075572130493 - 213 = 12075572122301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12075572130473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6037786065246 + 6037786065247.
It is an arithmetic number, because the mean of its divisors is an integer number (6037786065247).
Almost surely, 212075572130493 is an apocalyptic number.
It is an amenable number.
12075572130493 is a deficient number, since it is larger than the sum of its proper divisors (1).
12075572130493 is an equidigital number, since it uses as much as digits as its factorization.
12075572130493 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1587600, while the sum is 49.
The spelling of 12075572130493 in words is "twelve trillion, seventy-five billion, five hundred seventy-two million, one hundred thirty thousand, four hundred ninety-three".
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