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12075572130493 is a prime number
BaseRepresentation
bin1010111110111001000000…
…1011111111001010111101
31120202102011101101002201111
42233232100023333022331
53040321232431133433
641403235151042021
72354300635352404
oct257562013771275
946672141332644
1012075572130493
113936248726aa3
1214303b0810311
1369794c384371
142da66466663b
1515e1a77ecdcd
hexafb902ff2bd

12075572130493 has 2 divisors, whose sum is σ = 12075572130494. Its totient is φ = 12075572130492.

The previous prime is 12075572130473. The next prime is 12075572130541. The reversal of 12075572130493 is 39403127557021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9988362030969 + 2087210099524 = 3160437^2 + 1444718^2 .

It is a cyclic number.

It is not a de Polignac number, because 12075572130493 - 213 = 12075572122301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12075572130473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6037786065246 + 6037786065247.

It is an arithmetic number, because the mean of its divisors is an integer number (6037786065247).

Almost surely, 212075572130493 is an apocalyptic number.

It is an amenable number.

12075572130493 is a deficient number, since it is larger than the sum of its proper divisors (1).

12075572130493 is an equidigital number, since it uses as much as digits as its factorization.

12075572130493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1587600, while the sum is 49.

The spelling of 12075572130493 in words is "twelve trillion, seventy-five billion, five hundred seventy-two million, one hundred thirty thousand, four hundred ninety-three".