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12080250007 = 71725750001
BaseRepresentation
bin10110100000000100…
…11111110010010111
31011011220010021122221
423100002133302113
5144220021000012
65314413403211
7605234300530
oct132002376227
934156107587
1012080250007
115139a936a1
122411799507
1311a6981937
1482854b687
154aa823507
hex2d009fc97

12080250007 has 4 divisors (see below), whose sum is σ = 13806000016. Its totient is φ = 10354500000.

The previous prime is 12080250001. The next prime is 12080250029. The reversal of 12080250007 is 70005208021.

12080250007 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12080250007 - 215 = 12080217239 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12080250001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 862874994 + ... + 862875007.

It is an arithmetic number, because the mean of its divisors is an integer number (3451500004).

Almost surely, 212080250007 is an apocalyptic number.

12080250007 is a deficient number, since it is larger than the sum of its proper divisors (1725750009).

12080250007 is an equidigital number, since it uses as much as digits as its factorization.

12080250007 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1725750008.

The product of its (nonzero) digits is 1120, while the sum is 25.

Adding to 12080250007 its reverse (70005208021), we get a palindrome (82085458028).

The spelling of 12080250007 in words is "twelve billion, eighty million, two hundred fifty thousand, seven".

Divisors: 1 7 1725750001 12080250007