120854410013119 has 2 divisors, whose sum is σ = 120854410013120. Its totient is φ = 120854410013118.

The previous prime is 120854410013093. The next prime is 120854410013137. The reversal of 120854410013119 is 911310014458021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 120854410013119 - 2⁵ = 120854410013087 is a prime.

It is a super-3 number, since 3×120854410013119³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120854410013419) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60427205006559 + 60427205006560.

It is an arithmetic number, because the mean of its divisors is an integer number (60427205006560).

Almost surely, 2^{120854410013119} is an apocalyptic number.

120854410013119 is a deficient number, since it is larger than the sum of its proper divisors (1).

120854410013119 is an equidigital number, since it uses as much as digits as its factorization.

120854410013119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34560, while the sum is 40.

The spelling of 120854410013119 in words is "one hundred twenty trillion, eight hundred fifty-four billion, four hundred ten million, thirteen thousand, one hundred nineteen".