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12089484133 is a prime number
BaseRepresentation
bin10110100001001011…
…01110001101100101
31011012112111102111121
423100211232031211
5144224401443013
65315343333541
7605405630266
oct132045561545
934175442447
1012089484133
115144220401
1224148b12b1
1311a8865a0c
1482987296d
154ab54958d
hex2d096e365

12089484133 has 2 divisors, whose sum is σ = 12089484134. Its totient is φ = 12089484132.

The previous prime is 12089484109. The next prime is 12089484139. The reversal of 12089484133 is 33148498021.

12089484133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7153438084 + 4936046049 = 84578^2 + 70257^2 .

It is a cyclic number.

It is not a de Polignac number, because 12089484133 - 25 = 12089484101 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12089484133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12089484139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6044742066 + 6044742067.

It is an arithmetic number, because the mean of its divisors is an integer number (6044742067).

Almost surely, 212089484133 is an apocalyptic number.

It is an amenable number.

12089484133 is a deficient number, since it is larger than the sum of its proper divisors (1).

12089484133 is an equidigital number, since it uses as much as digits as its factorization.

12089484133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 165888, while the sum is 43.

The spelling of 12089484133 in words is "twelve billion, eighty-nine million, four hundred eighty-four thousand, one hundred thirty-three".