Base | Representation |
---|---|
bin | 11011100000110010000010… |
… | …101011100011111001011111 |
3 | 120212102111011211010102111121 |
4 | 123200302002223203321133 |
5 | 111324431010321321343 |
6 | 1105202345425431411 |
7 | 34325651034356524 |
oct | 3340620253437137 |
9 | 525374154112447 |
10 | 121000011120223 |
11 | 356108a88a4974 |
12 | 116a2742a9b567 |
13 | 5269337ab9c11 |
14 | 21c4608b6d14b |
15 | dec74bd66aed |
hex | 6e0c82ae3e5f |
121000011120223 has 2 divisors, whose sum is σ = 121000011120224. Its totient is φ = 121000011120222.
The previous prime is 121000011120161. The next prime is 121000011120283. The reversal of 121000011120223 is 322021110000121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121000011120223 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 121000011120197 and 121000011120206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121000011120283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60500005560111 + 60500005560112.
It is an arithmetic number, because the mean of its divisors is an integer number (60500005560112).
Almost surely, 2121000011120223 is an apocalyptic number.
121000011120223 is a deficient number, since it is larger than the sum of its proper divisors (1).
121000011120223 is an equidigital number, since it uses as much as digits as its factorization.
121000011120223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 121000011120223 its reverse (322021110000121), we get a palindrome (443021121120344).
The spelling of 121000011120223 in words is "one hundred twenty-one trillion, eleven million, one hundred twenty thousand, two hundred twenty-three".
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