Base | Representation |
---|---|
bin | 1011000000010100000011… |
… | …0011100001010000001011 |
3 | 1120211202020111202121100111 |
4 | 2300011000303201100023 |
5 | 3041221310042321303 |
6 | 41422400134015151 |
7 | 2356124350010665 |
oct | 260050063412013 |
9 | 46752214677314 |
10 | 12100010120203 |
11 | 39456492a2405 |
12 | 1435090aa74b7 |
13 | 69a0453337c5 |
14 | 2db902115535 |
15 | 15eb37ea8b6d |
hex | b0140ce140b |
12100010120203 has 2 divisors, whose sum is σ = 12100010120204. Its totient is φ = 12100010120202.
The previous prime is 12100010120183. The next prime is 12100010120221. The reversal of 12100010120203 is 30202101000121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12100010120203 - 25 = 12100010120171 is a prime.
It is a super-2 number, since 2×121000101202032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12100020120203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050005060101 + 6050005060102.
It is an arithmetic number, because the mean of its divisors is an integer number (6050005060102).
Almost surely, 212100010120203 is an apocalyptic number.
12100010120203 is a deficient number, since it is larger than the sum of its proper divisors (1).
12100010120203 is an equidigital number, since it uses as much as digits as its factorization.
12100010120203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 12100010120203 its reverse (30202101000121), we get a palindrome (42302111120324).
The spelling of 12100010120203 in words is "twelve trillion, one hundred billion, ten million, one hundred twenty thousand, two hundred three".
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