Base | Representation |
---|---|
bin | 10001100110111001110… |
… | …000001111100111011011 |
3 | 11021200020010200122120021 |
4 | 101212321300033213123 |
5 | 124311041033221021 |
6 | 2323511203211311 |
7 | 153263661233323 |
oct | 21467160174733 |
9 | 4250203618507 |
10 | 1210002242011 |
11 | 4271827a2602 |
12 | 17660b376b37 |
13 | 8a1448ab7c4 |
14 | 427c8ab2283 |
15 | 2171cd8cc41 |
hex | 119b9c0f9db |
1210002242011 has 2 divisors, whose sum is σ = 1210002242012. Its totient is φ = 1210002242010.
The previous prime is 1210002241999. The next prime is 1210002242017. The reversal of 1210002242011 is 1102422000121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1210002242011 - 25 = 1210002241979 is a prime.
It is a super-2 number, since 2×12100022420112 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1210002242017) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605001121005 + 605001121006.
It is an arithmetic number, because the mean of its divisors is an integer number (605001121006).
Almost surely, 21210002242011 is an apocalyptic number.
1210002242011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1210002242011 is an equidigital number, since it uses as much as digits as its factorization.
1210002242011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64, while the sum is 16.
Adding to 1210002242011 its reverse (1102422000121), we get a palindrome (2312424242132).
The spelling of 1210002242011 in words is "one trillion, two hundred ten billion, two million, two hundred forty-two thousand, eleven".
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