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121001020120133 is a prime number
BaseRepresentation
bin11011100000110010111110…
…110100100101110001000101
3120212102120210010201221011122
4123200302332310211301011
5111324440042122321013
61105203033512043325
734326015035623316
oct3340627664456105
9525376703657148
10121001020120133
113561127640549a
12116a2984993545
135269468b5869a
1421c46a2b8060d
15dec7aa724a08
hex6e0cbed25c45

121001020120133 has 2 divisors, whose sum is σ = 121001020120134. Its totient is φ = 121001020120132.

The previous prime is 121001020120091. The next prime is 121001020120229. The reversal of 121001020120133 is 331021020100121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 117520191092929 + 3480829027204 = 10840673^2 + 1865698^2 .

It is a cyclic number.

It is not a de Polignac number, because 121001020120133 - 220 = 121001019071557 is a prime.

It is a super-2 number, since 2×1210010201201332 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121001020120433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60500510060066 + 60500510060067.

It is an arithmetic number, because the mean of its divisors is an integer number (60500510060067).

Almost surely, 2121001020120133 is an apocalyptic number.

It is an amenable number.

121001020120133 is a deficient number, since it is larger than the sum of its proper divisors (1).

121001020120133 is an equidigital number, since it uses as much as digits as its factorization.

121001020120133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 121001020120133 its reverse (331021020100121), we get a palindrome (452022040220254).

The spelling of 121001020120133 in words is "one hundred twenty-one trillion, one billion, twenty million, one hundred twenty thousand, one hundred thirty-three".