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121001113 is a prime number
BaseRepresentation
bin1110011011001…
…01010010011001
322102200111022201
413031211102121
5221434013423
620001250201
72666330632
oct715452231
9272614281
10121001113
1162335a22
1234633961
131c0b77bc
14120da889
15a9522ad
hex7365499

121001113 has 2 divisors, whose sum is σ = 121001114. Its totient is φ = 121001112.

The previous prime is 121001099. The next prime is 121001141. The reversal of 121001113 is 311100121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 74597769 + 46403344 = 8637^2 + 6812^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121001113 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 121001113.

It is not a weakly prime, because it can be changed into another prime (121001213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60500556 + 60500557.

It is an arithmetic number, because the mean of its divisors is an integer number (60500557).

Almost surely, 2121001113 is an apocalyptic number.

It is an amenable number.

121001113 is a deficient number, since it is larger than the sum of its proper divisors (1).

121001113 is an equidigital number, since it uses as much as digits as its factorization.

121001113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 10.

The square root of 121001113 is about 11000.0505907928. The cubic root of 121001113 is about 494.6102608479.

Adding to 121001113 its reverse (311100121), we get a palindrome (432101234).

The spelling of 121001113 in words is "one hundred twenty-one million, one thousand, one hundred thirteen".