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12100113253 is a prime number
BaseRepresentation
bin10110100010011100…
…10001001101100101
31011020021111102220201
423101032101031211
5144240112111003
65320403230501
7605565160054
oct132116211545
934207442821
1012100113253
11514a2201a8
122418378431
1311aab17a37
1482b03c39b
154ac448b1d
hex2d1391365

12100113253 has 2 divisors, whose sum is σ = 12100113254. Its totient is φ = 12100113252.

The previous prime is 12100113241. The next prime is 12100113331. The reversal of 12100113253 is 35231100121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9745243524 + 2354869729 = 98718^2 + 48527^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12100113253 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12100113253.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12100113853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050056626 + 6050056627.

It is an arithmetic number, because the mean of its divisors is an integer number (6050056627).

Almost surely, 212100113253 is an apocalyptic number.

It is an amenable number.

12100113253 is a deficient number, since it is larger than the sum of its proper divisors (1).

12100113253 is an equidigital number, since it uses as much as digits as its factorization.

12100113253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180, while the sum is 19.

Adding to 12100113253 its reverse (35231100121), we get a palindrome (47331213374).

The spelling of 12100113253 in words is "twelve billion, one hundred million, one hundred thirteen thousand, two hundred fifty-three".