Base | Representation |
---|---|
bin | 1011000000010100011101… |
… | …1110010110000110010011 |
3 | 1120211202112022022012022011 |
4 | 2300011013132112012103 |
5 | 3041222022213310003 |
6 | 41422415212123351 |
7 | 2356130206033216 |
oct | 260050736260623 |
9 | 46752468265264 |
10 | 12100122010003 |
11 | 39456a6474915 |
12 | 1435102466557 |
13 | 69a06257b0a1 |
14 | 2db912d1d77d |
15 | 15eb42c0b46d |
hex | b0147796193 |
12100122010003 has 2 divisors, whose sum is σ = 12100122010004. Its totient is φ = 12100122010002.
The previous prime is 12100122009991. The next prime is 12100122010033. The reversal of 12100122010003 is 30001022100121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12100122010003 - 217 = 12100121878931 is a prime.
It is not a weakly prime, because it can be changed into another prime (12100122010033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050061005001 + 6050061005002.
It is an arithmetic number, because the mean of its divisors is an integer number (6050061005002).
Almost surely, 212100122010003 is an apocalyptic number.
12100122010003 is a deficient number, since it is larger than the sum of its proper divisors (1).
12100122010003 is an equidigital number, since it uses as much as digits as its factorization.
12100122010003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 12100122010003 its reverse (30001022100121), we get a palindrome (42101144110124).
The spelling of 12100122010003 in words is "twelve trillion, one hundred billion, one hundred twenty-two million, ten thousand, three".
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