12100124143 has 2 divisors, whose sum is σ = 12100124144. Its totient is φ = 12100124142.

The previous prime is 12100124131. The next prime is 12100124159. The reversal of 12100124143 is 34142100121.

It is a weak prime.

It is an emirp because it is prime and its reverse (34142100121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12100124143 - 2⁹ = 12100123631 is a prime.

It is a super-2 number, since 2×12100124143² (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12100124143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12100124123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050062071 + 6050062072.

It is an arithmetic number, because the mean of its divisors is an integer number (6050062072).

Almost surely, 2^12100124143 is an apocalyptic number.

12100124143 is a deficient number, since it is larger than the sum of its proper divisors (1).

12100124143 is an equidigital number, since it uses as much as digits as its factorization.

12100124143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 12100124143 its reverse (34142100121), we get a palindrome (46242224264).

The spelling of 12100124143 in words is "twelve billion, one hundred million, one hundred twenty-four thousand, one hundred forty-three".