Base | Representation |
---|---|
bin | 10001100110111010011… |
… | …001011001111011010011 |
3 | 11021200020212222211211221 |
4 | 101212322121121323103 |
5 | 124311101314012042 |
6 | 2323512230345511 |
7 | 153264152033413 |
oct | 21467231317323 |
9 | 4250225884757 |
10 | 1210013032147 |
11 | 4271888a2377 |
12 | 176612abb297 |
13 | 8a146bb8bba |
14 | 427ca2c0643 |
15 | 2171dcbed67 |
hex | 119ba659ed3 |
1210013032147 has 2 divisors, whose sum is σ = 1210013032148. Its totient is φ = 1210013032146.
The previous prime is 1210013032133. The next prime is 1210013032243. The reversal of 1210013032147 is 7412303100121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1210013032147 - 239 = 660257218259 is a prime.
It is not a weakly prime, because it can be changed into another prime (1210013032127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605006516073 + 605006516074.
It is an arithmetic number, because the mean of its divisors is an integer number (605006516074).
Almost surely, 21210013032147 is an apocalyptic number.
1210013032147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1210013032147 is an equidigital number, since it uses as much as digits as its factorization.
1210013032147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 1210013032147 its reverse (7412303100121), we get a palindrome (8622316132268).
The spelling of 1210013032147 in words is "one trillion, two hundred ten billion, thirteen million, thirty-two thousand, one hundred forty-seven".
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