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121002020201102 = 260501010100551
BaseRepresentation
bin11011100000110011111010…
…011011100110001010001110
3120212102200100211120022100112
4123200303322123212022032
5111324444114132413402
61105203321035200022
734326051601312265
oct3340637233461216
9525380324508315
10121002020201102
1135611739984097
12116a30038a6012
1352695980c3681
1421c475990d5dc
15dec81841ee52
hex6e0cfa6e628e

121002020201102 has 4 divisors (see below), whose sum is σ = 181503030301656. Its totient is φ = 60501010100550.

The previous prime is 121002020201011. The next prime is 121002020201107. The reversal of 121002020201102 is 201102020200121.

121002020201102 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121002020201107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30250505050274 + ... + 30250505050277.

It is an arithmetic number, because the mean of its divisors is an integer number (45375757575414).

Almost surely, 2121002020201102 is an apocalyptic number.

121002020201102 is a deficient number, since it is larger than the sum of its proper divisors (60501010100554).

121002020201102 is an equidigital number, since it uses as much as digits as its factorization.

121002020201102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60501010100553.

The product of its (nonzero) digits is 32, while the sum is 14.

Adding to 121002020201102 its reverse (201102020200121), we get a palindrome (322104040401223).

The spelling of 121002020201102 in words is "one hundred twenty-one trillion, two billion, twenty million, two hundred one thousand, one hundred two".

Divisors: 1 2 60501010100551 121002020201102